1.) A 1.0 uF (u = micro) capacitor is charged to 5.0 uC. What is the voltage acr

Question

  1.) A 1.0 uF (u = micro) capacitor is charged to 5.0 uC.  What is the voltage across it?            1a.) The same 1.0 uF (u = micro) capacitor is still charged to 5.0 uC.  What is the energy stored in it, in J?     1b.) The same 1.0 uF (u = micro) capacitor is still charged to 5.0 uC.  It is isolated; there is no battery or other device.  A second, identical capacitor is connected in parallel to it.  The charge redistributes until it reaches equilibrium.  What is the total energy now stored on both capacitors, in J?  Hint: what is conserved when the second capacitor is connected? 

Explanation / Answer

1) Q = CV

5 uC = 1uF V

V = 5 Volts

2) E = 1/2 C V^2 = 1/2* 1.0E-6 * 5^2 = 12.5E-6 J

b) each will have E = Q^2/2C = (2.5E-6)^2/(2*1.0E-6)=3.125E-6 J

so total energy = 6.25E-6 J

Related Questions

Navigate

• Browse (All)
• Browse 1
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.