please help A 6.0 kg box is held at rest by two ropes that form 30 degree angles

Question

please help

A 6.0 kg box is held at rest by two ropes that form 30 degree angles with the vertical. An external force F acts vertically downward on the box. The force exerted by each of the two ropes is denoted by T. A force diagram, showing the four forces that act on the box in equilibrium, is shown in the figure. The magnitude of force F is 410 N. The magnitude of force T is closest to: 271 N 235 N 376 N 470 N 188 N A15 kg block is on a ramp that is inclined at 20 degree above the horizontal. It is connected by a string to a 19 kg mass that hangs over the top edge of the ramp. Assuming that frictional forces may be neglected, what is the magnitude of the acceleration of the 19 kg block? (See the figure.) 3.8 m/s2 4.2 m/s2 4.0 m/s2 4.5 m/s2 The figure shows two 1.0 kg blocks connected by a rope. A second rope hangs beneath the lower block. Both ropes have a mass of 250 g. The entire assembly is accelerated upward at 2.3 m/s 2 by force What is the tension at the top end of rope 1? 2.9 N 18 N 3.5 N 15

Explanation / Answer

Relevant equations
w = mg

Fnet = ma

cos [theta] = adjacent/hypotenuse



3. The attempt at a solution
w = mg
fW = mg = 6.0 kg * -9.8 m/s2 =-58.8 N

Fnet = ma
Fnet, negative-y-axis = -58.8 N + (-410 N) = -469 N

469 N force is balance by the components of 2 Ts in the vertical direction.
So 2*T*cos(30) = 469.

T = 271N

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