Question
please answer all
An AC source operating at 60 Hz with a maximum voltage of 161 V is connected in series with a resistor (R = 1.2 k Ohm) and a capacitor (C = 2.5 micro F). What is the maximum value of the current in the circuit? Your response differs from the correct answer by more than 10%. Double check your calculations. A What are the maximum values of the potential difference across the resistor and the capacitor? Delta V R,max = Your response differs from the correct answer by more than 10%. Double check your calculations. V Delta V C, max = The correct answer is not zero. V When the current is zero, what are the magnitudes of the potential difference across the resistor, the capacitor, and the AC source? Delta V R = Delta V C = The correct answer is not zero. V Delta V source = Your response differs from the correct answer by more than 10%. Double check your calculations. V How much charge is on the capacitor at this instant? Delta qc = The correct answer is not zero. micro C When the current is at a maximum, what are the magnitudes of the potential differences across the resistor, the capacitor, and the AC source? Delta V R = The correct answer is not zero. V Delta V C = Delta V source = Your response differs from the correct answer by more than 10%. Double check your calculations. V How much charge is on the capacitor at this instant? Delta qc = micro C
Explanation / Answer
V max=161 V===>R=1200 ohms===>C=2.5 uF===>Hz=60===>XC=1/(2*pi*f*C)=1061.033 ohms
Z=sqrt(R^2+XC^2)=1601.81 ohms===>161 V max/Z=100.51 mA max
a) 100.51 mA max
b) VR max=100.51 mA*1200 ohms=120.614 V===>VC max=100.51 mA*XC=106.65 V
c) VR=0 V===>VS=sqrt(VR^2+VC^2)===>sqrt(161^2)=12.69 V=VC===>VS=161 V max===>
q=C*V=2.5 uF*12.69 V=31.72 uC
d) VR=12.69 V===>VC=0 V===>VS=161 V===>q=C*V=0 uC
