Sunlight strikes a piece of crown glass at an angle of incidence of 30.3 deg . A

Question

Sunlight strikes a piece of crown glass at an angle of incidence of 30.3 deg.

A. Calculate the difference in the angle of refraction between a orange (610 nm) and a blue (470 nm) ray within the glass. The index of refraction is n=1.522 for orange and n=1.531 for blue light.

B.The ray now travels inside the glass. What is the minimum angle of incidence at which the orange ray can hit the surface of the glass and become there totally internally reflected and not refracted?

in

Explanation / Answer

1)so for orange: 1*sin (30.3)=1.522* sin (theta 2) so 0.5045=1.522*sin (theta 2) sin (theta 2)=0.5045/1.522 sin(theta)=0.3314 >>> to find theta you do (sin^-1 of 0.3314)= 19.353 degrees for orange. for blue same thing: 1*sin(30.3)=1.531*sin(theta 2) 0.5045=1.531*sin (theta 2) sin(theta 2)= 0.5045/1.531 sin(theta 2)=0.3295>>>>> theta = sin^-1 of 0.3295= 19.238 degrees for blue. orange-blue=19.353-19.238=0.115 so your answer is 0.115!!! 2) sin i/sin90 = 1/1.522 i=41o There for angle of incidence should be greater than 41o

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