B)The man completely inhales and jumps into the deep end of a pool with a depth

Question

B)The man completely inhales and jumps into the deep end of a pool with a depth of 9 feet. The man swims to the bottom of a pool and stands erect on the bottom of the pool for a moment at rest. The man then accelerates upward due to an unbalanced vertical force (the buoyant force of the water acting on the man is greater than the weight of the man); the man moves upward 3 feet (0.914m) in 5.59 seconds when his head breaks the surface of the water.

1)Calculate the net acceleration of the man with his breath completely inhaled while totally submerged in the water.
2)Calculate the buoyant force of the water acting on the man with his breath completely inhaled.
3)Calculate the volume of the man with his breath completely inhaled.

C)Calculate the amount of air the man took in his breath for Part

Explanation / Answer

1) x = 1/2 a t^2

0.914 = 0.5*a*5.59^2
a=0.0585 m/s^2

2) F bouyancy = m*a
you didnt give us m but just multiply by the number in part a

3) use that F = d V g

so F from part b = 1000*v*9.81

solve for V

C) need the previous part but you would just subtract the volumes

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