\"https://media.cheggcdn.com/media/7b4/7b44612a-b47e-4b9c-aa47-714f5afc485f/php7

Question

"https://media.cheggcdn.com/media/7b4/7b44612a-b47e-4b9c-aa47-714f5afc485f/php7Y0mSy.png" />

"color: rgb(25, 33, 104); font-family: Verdana, Arial, Helvetica, sans-serif; line-height: 16px;">

A man is standing on a turntable that is on a frictionless axle.

Initially he is stationary. Then a ball of

massm=2.1kg is thrown directly into

his hand at a

speedvo=9.85m/s. With his

arm outstretched, the distance from his shoulder (at the axis of

rotation) isd=0.65m

and

"font-family: serif; font-style: normal; line-height: normal;">

"http://loncapa.mines.edu/adm/jsMath/fonts/cmmi10/alpha/100/char12.png"

style=

"width: 7px; vertical-align: -1px; margin-right: -0.034em;" />

=38.2degrees.

He catches and holds the ball. When he catches the ball, the man's

moment of inertia (not including the ball)

isIo=0.59kgm2.

"color: rgb(25, 33, 104); font-family: Verdana, Arial, Helvetica, sans-serif; line-height: 16px;">

What is the final angular velocity of the man right after the ball

is caught?

How do you do this problem? I can't seem to solve this problem

without the mans mass. Is there a way to find his mass?

Explanation / Answer

conservation of ang momentum

I1*omega1=I2*omega2

I1=m(ball) * r^2=2.1 * (.65 cos 38.2)^2=.548

omega1=v/r=9.85/(.65 cos 38.2)=19.28

I2=(I1+Iman)=.548+.59=1.138

so omega2=I1*omega1/I2=9.28 rad/s

Related Questions

Navigate

• Browse (All)
• Browse #
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.