2. A guy is spinning initially at a constant rate with his arms at his sides. He
ID: 2111111 • Letter: 2
Question
2. A guy is spinning initially at a constant rate with his arms at his sides. He then puts his arms straight out. His arms are 80 cm each and he has a wing span of 2.0 m. Each arm has a mass of about 10 kg (assume his arms are uniform cylinders.) a) How much does his moment of inertia change when he sticks his arms out? b) How much does his angular momentum change when he sticks his arms out? 2. A guy is spinning initially at a constant rate with his arms at his sides. He then puts his arms straight out. His arms are 80 cm each and he has a wing span of 2.0 m. Each arm has a mass of about 10 kg (assume his arms are uniform cylinders.) a) How much does his moment of inertia change when he sticks his arms out? b) How much does his angular momentum change when he sticks his arms out?Explanation / Answer
M.I of each arm about his body=1/2(1/2mr^2)=1/4mr^2
( a)change in M.I=2*1/4mr^2=1/2mr^2=1/2*10*(0.8)^2=3.2 kg-m^2 ans
b)since no external torque is acting
angular momentum will be conserved
hence change in angular momentum=0
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