solve TWO SLIT INTERFERENCE: A coherent electromagnetic wave of wavelength 520 n

Question

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TWO SLIT INTERFERENCE: A coherent electromagnetic wave of wavelength 520 nm passes through two thin slits that are a distance d = 0.0400 mm apart. The light then falls on a screen a distance R = 70.0 cm away. How far away from the center of the central bright fringe on the screen is the 3rd bright fringe (not counting the central bright fringe) How far away from the center of the central bright fringe on the screen is the 3rd dark fringe? Also, please compute the difference between this answer and the answer you got in part (a). How far away from the center of the central bright fringe on the screen is the 1st dark fringe? From your answer to part (c), what is the width of the central maximum? In this problem, in what range is the electromagnetic wave ? Circle one: x-ray range (ii) visible range (iii) ultra-violet range (iv) in the range of radio waves

Explanation / Answer

Part A)
Apply y/L = m(wavelength)/d

y/.7 = (3)(520 X 10^-9)/(4 X 10^-5)

y = .0273 m which is 2.73 cm

Part B)

y/.7 = (2.5)(520 X 10^-9)/(4 X 10^-5)

y = .02275 m which is 2.275 cm

The difference between this and part a is 2.73 - 2.275 = 4.55 mm

Part C)

y/.7 = (.5)(520 X 10^-9)/(4 X 10^-5)

y = 4.55 X 10^-3 m which is 4.55 mm

Part D)

The width of the central maximum is twice the answer to part C, that is 9.1 X 10^-3 m (9.1 mm)

Part E)

This wavelength in in the visible spectrum (Choice ii)

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