A spaceship moves with velocity 0.6c with respect to the Earth. At midnight it p

Question

A spaceship moves with velocity 0.6c with respect to the Earth. At midnight it passes Earth, and observers on both the spaceship and on Earth agree that their clocks read midnight. At 12:50 A.M. (spaceship time) the spaceship passes an interplanetary navigational station and sends a radio signal back to Earth. The receiving antenna on earth, immediately on receiving this signal, responds by sending a signal back to the spaceship. The following questions refer to this series of events.

At what time did the spceship passthenavigational station(Earth-Based Time)?

a. 1:02:30 AM
b. 1:1 AM
c. 12:50 AM
d. 12:45:30 AM
e. 12:40 AM

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Explanation / Answer

These equations might help: ?=11-v2/c2--------v w'=w-v1-wv/c2 If the observer in S sees an object moving along the x axis at velocity w, then the observer in the S' system, a frame of reference moving at velocity v in the x direction with respect to S, will see the object moving with velocity w'. M=Ec2 mrel=m1-v2c2-----v mrel=relativistic mass. Oh and for part one you might want to convert .6c into m/s so you are using the same units. Might make it easier. Edit: Oh and: t'=t-vx/c2

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