A car race takes place on a long straight track, at the beginning of the race th

a) 0.5*1.13*t^2 + (1.13*t)*(2.05*60-t) = 2411 So, t = 18.8 s

ID: 2112210 • Letter: A

Question

A car race takes place on a long straight

track, at the beginning of the race the car accelerates from rest to some top

speed with a (constant) acceleration of 1.13 m/s2 and then maintains that top

speed to the end of the race. The total time taken from the start of the race

to the end is 2.05 minutes and the total distance covered is 2.41 km. (a) What

was the time elapsed during the acceleration phase of the cars motion? (b) What

distance did the car cover during the acceleration phase of its motion? (c)

What was the top speed reached by the car?

0.5*1.13*t^2 + (1.13*t)*(2.05*60-t) = 2411

So, t = 18.8 s <----------answer

distance = 0.5*1.13*18.8^2 =199.3 m

top speed = 1.13*18.78 = 21.2 m/s

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