full points to anyone who answers in detail all of the questions An infinitely l
ID: 2112970 • Letter: F
Question
full points to anyone who answers in detail all of the questions
Explanation / Answer
a)
consider a solid cylinder with no hollow part in it -->C1
and consider a solid cylinder which fits perfectly to the hollow part--->C2
E1 from C1 is
by guass law
E1 = q1/(e*2pi r1*l)
where e is epselon
r1 is the radial distance from A
l is the length of the guassian cylinder considered
q1= 10.0 * pi*r1*r1*l*10^(-6)
E1=10^(-5)*r1/2e in radially outward direction w.r.t center A
let the center point between A and B is C
then we have for Cylinder C2
E2 = q2/(e*2pi*r2*l)
where
r2 is the radial distance from C
l is the length of the guassian cylinder considered
q2= 10.0 * pi*r2*r2*l*10^(-6)
E2=10^(-5)*r2/2e in radially outward direction w.r.t center C
so the actual electric field is
E1-E2= 10^(-5)*(r1+r2) / 2e from A to C as radially outward is in opposite direction
E1 - E2 = 10^(-5)*(r1-r2) / 2e from C to B as radially outward is in same direction
b) for point A r1=0 and r2=2.5
for point B r1=5 and r2=2.5
so EA= 10^(-5)*2.5/(2e)
EB= 10^(-5)*2.5/(2e)
along the straight line AB
from A to C
we have
potential difference = 10^(-5)*2.5*2.5/4e
form C to B
we have
potential difference = 10^(-5)*2.5*2.5/4e
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