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Two masses are suspended by cord that passes over a pulley with negligible mass.

ID: 2114456 • Letter: T

Question

Two masses are suspended by cord that passes over a pulley with negligible mass. The cord also has negligible mass. One of the masses, m1, has a mass of 5.0 kg and the other mass, m2, has a mass of 3.0 kg. The acceleration of m1 is (0.5pts) 2.5 m/s2 upward. 3.3 m/s2 downward. 3.3 m/s2 upward. 2.5 m/s2 downward. 1.1 m/s2 upward. Two masses are suspended by cord that passes over a pulley with negligible mass. The cord also has negligible mass. One of the masses, m1, has a mass of 5.0 kg and the other mass, m2, has a mass of 3.0 kg. The acceleration of m1 is (0.5pts) 2.5 m/s2 upward. 3.3 m/s2 downward. 3.3 m/s2 upward. 2.5 m/s2 downward. 1.1 m/s2 upward. 2.5 m/s2 upward. 3.3 m/s2 downward. 3.3 m/s2 upward. 2.5 m/s2 downward. 1.1 m/s2 upward. 2.5 m/s2 upward. 2.5 m/s2 upward. 2.5 m/s2 upward. 3.3 m/s2 downward. 3.3 m/s2 downward. 3.3 m/s2 downward. 3.3 m/s2 upward. 3.3 m/s2 upward. 3.3 m/s2 upward. 2.5 m/s2 downward. 2.5 m/s2 downward. 2.5 m/s2 downward. 1.1 m/s2 upward. 1.1 m/s2 upward. 1.1 m/s2 upward.

Explanation / Answer

the masses are m1 = 5.0 kg and m2 = 3.0 kg

the acceleration of the masses is

a = (m1 - m2/m1 + m2) * g

where g = 9.8 m/s^2

the acceleration of mass m1 is downward

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