explain please! A uniform beam of length l = 3m and mass m = 10 kg leans against
ID: 2114557 • Letter: E
Question
explain please!
A uniform beam of length l = 3m and mass m = 10 kg leans against a vertical wall. The floor is horizontal, and everything is near Earth. Complete the problem laid out in class on 3 June. Call the angle the slip angle. If the coefficient of friction between the floor and the beam is reduced to 0.3, what is the new "slip" angle? Is (Are) there any condition(s) on the coefficient of friction between the beam and the wall that will allow for the same "slip" angle from part (a) in part (b)? If so, what is (are) the condition(s)?Explanation / Answer
Let the slip angle phi be from the angle between the beam and the horizontal ground.
the coefficient of friction between the floor and the beam is 0.3.
thus normal force = 10g
force of friction will be 100*0.3 = 30N
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