6. The above figure shows a double loop circuit containing 2 voltage sources (em
ID: 2114742 • Letter: 6
Question
6. The above figure shows a double loop circuit containing 2 voltage sources (emfs) and 3 resistors.
(a) Using Kirchhoff%u2019s junction rule, write an equation that relates I1, I2 and I3.
(b) Using Kirchhoff%u2019s loop rule, write an equation in its simplest form that relates the potential differences around the loop abcda.
(c) Using Kirchhoff%u2019s loop rule, write an equation in its simplest form that relates the potential differences around the loop befcb.
The potential difference between b and c was measured as 2 V with b at the higher potential.
Calculate
(d) the potential difference across the 6 W resistor.
(e) I1
(f) I3
(g) I2
(h) the power delivered to the 2 W resistor.
Explanation / Answer
a)at c,
I1 + I2 = I3
b)-10 + 6I1 + 2I3=0
c)-10 + 6I1 -14 - 4I2=0
d)around b and c,
-10+6I1 = 2
I1=2A potential diff across 2 is = 6*2=12V
e)I1=2A
f)eqns:
solving eqn of a) b) and c)
we get
22I1=44
I1=2
2I2 +16 +10
I2=-3A
I3=I1 + I2
I3=-1A
g)I2=-3A
h)power=(I3)^2 * 2= 2Watts
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