.. A long, straight wire carries a current of 5.20 A. An electron is traveling i

Question

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A long, straight wire carries a current of 5.20 A. An electron is traveling in the vicinity of the wire. At the instant when the electron is 4.20cm from the wire and traveling with a speed of 6.20times104 m/s directly toward the wire, what is the magnitude of the force that the magnetic field of the current exerts on the electron? What is the direction (relative to the direction of the current) of this force? opposite to the current in the same direction as the current perpendicular to the current

Explanation / Answer

A)

magnitude of force = BId

B = uI/(2*pi*r) = 1.26*10^-6*5.2/(2*3.14*0.042) = 2.48*10^-5

So, force = qvB = 1.6*10^-19*(6.2*10^4)*(2.48*10^-5) = 2.46*10^-19 N <-----answer

B)

same direction to the current

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