Academic Integrity: tutoring, explanations, and feedback — we don’t complete graded work or submit on a student’s behalf.

Question Part Points Submissions Used 1 0 /5 3/5 Total 0 /5 An automobile with 0

ID: 2115705 • Letter: Q

Question

Question Part Points Submissions Used 1 0/5 3/5 Total 0/5 An automobile with 0.260 m radius tires travels 95,000 km before wearing them out. How many revolutions do the tires make, neglecting any backing up and any change in radius due to wear? show work please Question Part Points Submissions Used 1 0/5 3/5 Total 0/5 An automobile with 0.260 m radius tires travels 95,000 km before wearing them out. How many revolutions do the tires make, neglecting any backing up and any change in radius due to wear? show work please Question Part Points Submissions Used 1 0/5 3/5 Total 0/5 Question Part Points Submissions Used 1 0/5 3/5 Total 0/5 Question Part Points Submissions Used 1 0/5 3/5 Total 0/5 Question Part Points Submissions Used 1 0/5 3/5 Total 0/5 Question Part Points Submissions Used 1 0/5 3/5 1 0/5 3/5 Total 0/5 An automobile with 0.260 m radius tires travels 95,000 km before wearing them out. How many revolutions do the tires make, neglecting any backing up and any change in radius due to wear? show work please An automobile with 0.260 m radius tires travels 95,000 km before wearing them out. How many revolutions do the tires make, neglecting any backing up and any change in radius due to wear? show work please Question Part Points Submissions Used

Explanation / Answer

Circumference of the wheel = 2(pie)r=2(pie)(0.26) = 0.52(pie)

Thus net revolutions = Total diatance travelled / Total circumference = 95000/(0.52%u03C0)

Hire Me For All Your Tutoring Needs
Integrity-first tutoring: clear explanations, guidance, and feedback.
Drop an Email at
drjack9650@gmail.com
Chat Now And Get Quote