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In part (a) of the diagra, a negatively charged particle moving at a velcocity v

ID: 2116662 • Letter: I

Question

In part (a) of the diagra, a negatively charged particle moving at a velcocity v in n evacuated space enters a region between capacitor places as shown. What direction is the E-field pointing in?
In part (b), a positively charged particle enters a sharply defined region of uniform B-field directed. What direction is the B-field pointing in?


Exam the following statments (true or false ) and explain the reason behind your conculsion.


a) the negatively charged particle in (a), on entering the electrical field between the capacitor plates, moves without change in the y-component of its velocity.


b) the negatively charged particle in (a), on entering the electrical field between the capacitor plates, moves without change in the x-component of its velocity.


c) the positively charged particle in (b), on entering the region of magnetic field , moves without change in the y-component of its velocity.


d) the positively charged particle in (b), on entering the region of magnetic field , moves without change in the x-component of its velocity.


e) Neither particle changes its speed as it continue along its trajectory.

Explanation / Answer

a). from left to right that is from positively charged plate to negatively charged plate

b).B is pointing in the downward direction going into the page

@).

a). true because the force will be in x- direction so no acceleration in y direction

b).false

as there is electric force acting in the charge in x - direction due to presence of electric field so its velocity will change


c).False

as the force will always be prependicular to its motion so there is a component in the y direction


so velocity will change

d)..False

as the force will always be prependicular to its motion so there is a component in the x direction


so velocity will change

e).False

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