6. You have a new set of data from Atwood\'s Machine with the setup from the exp

Question

6. You have a new set of data from Atwood's Machine with the setup from the experiment as outlined in the lab manual. You get a trend-line whose equation is
y = 0.2368 x + 0.016.
What is likely the measured acceleration of massone if massone = 0.0934 [kg]
and masstwo = 0.1084 [kg]?
[ms-2]
Use three significant figures or N/A if there is not enough information.
When working with numbers that have more significant figures than your answer requires, carry all digits until your final answer! And, yes, we know that the mass1 and mass2 above don't add up to be the effective mass; they didn't in your experiment either!

Explanation / Answer

acceleration of mass 1 = d^2y/dt^2 = 0.2368 *accleration of mass2

so, m1g -T= m1a1

T=m2a2

so, m1g-m2a2 = m1a1

so, m1g-m2 a2 = m1*0.2368*a2

so, 0.0934*9.8 -0.1084 a2 = 0.0934*0.2368*a2

solving, a2 =acceleration of mass2 = 7.013 m/s^2

acceleration of mass1 = 0.2368*a1 = 1.661 m/s^2

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