To practice Problem-Solving Strategy 11.1 Equilibrium of a Rigid Body. A horizon

Question

To practice Problem-Solving Strategy 11.1 Equilibrium of a Rigid Body. A horizontal uniform bar of mass 2.4kg and length 3.0 m is hung horizontally on two vertical strings. String 1 is attached to the end of the bar, and string 2 is attached a distance 0.7m from the other end. A monkey of mass 1.2kg walks from one end of the bar to the other. Find the tension T1 in string 1 at the moment that the monkey is halfway between the ends of the bar.
PartA For the bar to experience no net force, what must be the tension T2 in string 2 when the monkey is halfway between the ends of the bar? Express your answer in newtons using three significant figures. To practice Problem-Solving Strategy 11.1 Equilibrium of a Rigid Body. A horizontal uniform bar of mass 2.4kg and length 3.0 m is hung horizontally on two vertical strings. String 1 is attached to the end of the bar, and string 2 is attached a distance 0.7m from the other end. A monkey of mass 1.2kg walks from one end of the bar to the other. Find the tension T1 in string 1 at the moment that the monkey is halfway between the ends of the bar.
PartA To practice Problem-Solving Strategy 11.1 Equilibrium of a Rigid Body. To practice Problem-Solving Strategy 11.1 Equilibrium of a Rigid Body. A horizontal uniform bar of mass 2.4kg and length 3.0 m is hung horizontally on two vertical strings. String 1 is attached to the end of the bar, and string 2 is attached a distance 0.7m from the other end. A monkey of mass 1.2kg walks from one end of the bar to the other. Find the tension T1 in string 1 at the moment that the monkey is halfway between the ends of the bar. For the bar to experience no net force, what must be the tension T2 in string 2 when the monkey is halfway between the ends of the bar? Express your answer in newtons using three significant figures.

Explanation / Answer

(m1+m2)*g*L/2=T2*(L-0.7)

==> T2=23 N

==> T1=(m1+m2)*g-T2=12.27 N

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