A long, straight wire carries a current of 2.3 A . The direction of the current

Question

A long, straight wire carries a current of 2.3 A. The direction of the current is shown in Figure with a red arrow. A particle with electric charge -4.6x10^-6 C (P in Figure) is moving at speed 34 m/s along the wire in direction F (See Figure). The distance between the wire and the charge is 2.5x10^-2 m.

(a) Find the magnitude and direction of the magnetic field at the position of the charge --> B= 1.8410^-5 T

(b) Determine the magnitude and direction of the force exerted on the charge by the magnetic field.

Explanation / Answer

a) B=u*I/2*pi*d

B= 2*10^-7 * 2.3/ 2.5 *10^-2 = 1.8410 * 10^-5T upwards ie in direction of U

b)F =qvB

F= -4.6x10^-6 * 34 * 1.8410 * 10^-5 = -2.877 * 10^-9N towards R

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