What is the capacitance of two parallel plates 0.9 mm apart with an area of 12 c

Question

What is the capacitance of two parallel plates 0.9 mm apart with an area of 12 cm2 if the space between the plates is filled with a material with dielectric constant of 3.7? 4.4 mF 3.7 %u03BCF 44 pF 130 %u03BCF 76 F What is the capacitance of two parallel plates 0.9 mm apart with an area of 12 cm2 if the space between the plates is filled with a material with dielectric constant of 3.7? 4.4 mF 3.7 %u03BCF 44 pF 130 %u03BCF 76 F What is the capacitance of two parallel plates 0.9 mm apart with an area of 12 cm2 if the space between the plates is filled with a material with dielectric constant of 3.7? 4.4 mF 3.7 %u03BCF 44 pF 130 %u03BCF 76 F What is the capacitance of two parallel plates 0.9 mm apart with an area of 12 cm2 if the space between the plates is filled with a material with dielectric constant of 3.7? 4.4 mF 3.7 %u03BCF 44 pF 130 %u03BCF 76 F What is the capacitance of two parallel plates 0.9 mm apart with an area of 12 cm2 if the space between the plates is filled with a material with dielectric constant of 3.7? 4.4 mF 3.7 %u03BCF 44 pF 130 %u03BCF 76 F What is the capacitance of two parallel plates 0.9 mm apart with an area of 12 cm2 if the space between the plates is filled with a material with dielectric constant of 3.7? 4.4 mF 3.7 %u03BCF 44 pF 130 %u03BCF 76 F What is the capacitance of two parallel plates 0.9 mm apart with an area of 12 cm2 if the space between the plates is filled with a material with dielectric constant of 3.7? 4.4 mF 3.7 %u03BCF 44 pF 130 %u03BCF 76 F What is the capacitance of two parallel plates 0.9 mm apart with an area of 12 cm2 if the space between the plates is filled with a material with dielectric constant of 3.7? 4.4 mF 3.7 %u03BCF 44 pF 130 %u03BCF 76 F What is the capacitance of two parallel plates 0.9 mm apart with an area of 12 cm2 if the space between the plates is filled with a material with dielectric constant of 3.7? 4.4 mF 3.7 %u03BCF 44 pF 130 %u03BCF 76 F What is the capacitance of two parallel plates 0.9 mm apart with an area of 12 cm2 if the space between the plates is filled with a material with dielectric constant of 3.7? 4.4 mF 3.7 %u03BCF 44 pF 130 %u03BCF 76 F What is the capacitance of two parallel plates 0.9 mm apart with an area of 12 cm2 if the space between the plates is filled with a material with dielectric constant of 3.7? 4.4 mF 3.7 %u03BCF 44 pF 130 %u03BCF 76 F What is the capacitance of two parallel plates 0.9 mm apart with an area of 12 cm2 if the space between the plates is filled with a material with dielectric constant of 3.7? 4.4 mF 3.7 %u03BCF 44 pF 130 %u03BCF 76 F What is the capacitance of two parallel plates 0.9 mm apart with an area of 12 cm2 if the space between the plates is filled with a material with dielectric constant of 3.7? 4.4 mF 3.7 %u03BCF 44 pF 130 %u03BCF 76 F What is the capacitance of two parallel plates 0.9 mm apart with an area of 12 cm2 if the space between the plates is filled with a material with dielectric constant of 3.7? 4.4 mF 3.7 %u03BCF 44 pF 130 %u03BCF 76 F What is the capacitance of two parallel plates 0.9 mm apart with an area of 12 cm2 if the space between the plates is filled with a material with dielectric constant of 3.7? 4.4 mF 3.7 %u03BCF 44 pF 130 %u03BCF 76 F What is the capacitance of two parallel plates 0.9 mm apart with an area of 12 cm2 if the space between the plates is filled with a material with dielectric constant of 3.7? 4.4 mF 3.7 %u03BCF 44 pF 130 %u03BCF 76 F What is the capacitance of two parallel plates 0.9 mm apart with an area of 12 cm2 if the space between the plates is filled with a material with dielectric constant of 3.7? 4.4 mF 3.7 %u03BCF 44 pF 130 %u03BCF 76 F What is the capacitance of two parallel plates 0.9 mm apart with an area of 12 cm2 if the space between the plates is filled with a material with dielectric constant of 3.7? 4.4 mF 3.7 %u03BCF 44 pF 130 %u03BCF 76 F 4.4 mF 4.4 mF 3.7 %u03BCF 3.7 %u03BCF 3.7 %u03BCF 44 pF 44 pF 44 pF 130 %u03BCF 130 %u03BCF 130 %u03BCF 76 F 76 F 76 F

Explanation / Answer

C= k e A/d

= 3.7*8.85*10^-12 *(.0012)/.0009

= 4.36 * 10^-11 F

44 pF

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