practical circuit line voltage is 120v and is driven by 60hz rating rms voltage.

Question

practical circuit line voltage is 120v and is driven by 60hz rating rms voltage. you have a component in your circuit that has an inductance of 5mh. the inductor is 0.1m long with an area of .001 msquared. A) how many turns must there be in the inductor? B) put the circuit in resonance, what should the capacitance be? C) the capacitor is replaced by a resistor of 2.0 k ohms what is the angle delay between the circuits current and voltage? D)what is the avg power output of resistor? E)you want 4x the power out the resistor design a transformer to make this possible where primary side of transformer is 500 turns? F) draw you resultant circuit including transformer labeling parts

Explanation / Answer

a) L = mu0*N^2*A/L = 4*pi*10^-7 *N^2*0.001/0.1

==> N = sqrt(5*10^-3/(4*pi*10^-7 *0.001/0.1)) = 630 turns

b) C = 1/w^2 L

w = 2*pi*60= 120*pi

so C = 1/((120*pi)^2*5*10^-3) = 0.014 = 14 mF

c)angle = arctan(wL/R) = arctan[(120*pi*5*10^-3)/(2*10^3)] = 0.054 degree

d) P = V^2/R = 120^2/(2*10^-3) = 7.2 W

e)Vs = 2Vp for 4x the power out

so Np/Ns = 1/2

==> Ns = 1000 turns

so the transformer will have 1000 turns on secondary side....

Related Questions

Navigate

• Browse (All)
• Browse P
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.