The left plate of a parallel plate capacitor carries a positive charge Q, and th

Question

The left plate of a parallel plate capacitor carries a positive charge Q, and the right plate carries a negative charge -Q. The magnitude of the electric field between the plates is 100 kV/m. The plates each have an area of 2 x 10-3 m2, and the spacing between the plates is 6 x 10-3 m. There is no dielectric between the plates. What is the charge on the capacitor?

Q =

The left plate of a parallel plate capacitor carries a positive charge Q, and the right plate carries a negative charge -Q. The magnitude of the electric field between the plates is 100 kV/m. The plates each have an area of 2 x 10-3 m2, and the spacing between the plates is 6 x 10-3 m. There is no dielectric between the plates. What is the magnitude of the potential difference across the capacitor plates?

V =

1)

|E|A =

2)That is the approximate strength of the electric field at point B?

|E|B =

Explanation / Answer

a) usingE = Q/AEo => Q = 1.77*10^-9 C

b) V =Ed = 600V

1) E = delta V/d = 10/.02 = 500 V/m

2) 1000 V/m

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