Starting from rest at t=0sec, a tire on a mountain bike has a constant angular a

Question

Starting from rest at t=0sec, a tire on a mountain bike has a constant angular acceleration. When t= 5 sec, the angular velocity of the wheel is 6.9 rad/sec. The angular acceleration continues until t= 16 sec, after which the angular velocity remains constant. The tire has a radius of 22cm. 1) What is the angular acceleration at t= 16 sec? ? = 1.38 rad/sec2 2) What is angular velocity at t= 16 sec? ? = 22.08 rad/sec 3) What is the total angular displacement of the tire from t=0sec to t=16 sec? ? = 176.64 rad 4) What would be the total displacement of a small stone stuck in the tread of the tire as it goes around from t=0sec to t=16 sec? ?s = 38.86 m 5) What would be the linear displacement of the tire's axle as it moves forward from t=0sec to t=16 sec? ?x = m All I need is 5 please help!!

Explanation / Answer

The answer to part e is the same as the answer to part d!

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