Assume a block is placed on the top of an upside down semi-spherical bowl. The b

Question

Assume a block is placed on the top of an upside down semi-spherical bowl. The block starts to slide without frictions. At what angle from the vartical will the block fly off the bowls surface? Now consider a circular ring instead of the block and the fact it will roll down the surface without slipping. What will be the value of the angle at which the ring will y o the bowl surface? Assume a block is placed on the top of an upside down semi-spherical bowl. The block starts to slide without frictions. At what angle from the vartical will the block fly off the bowls surface? Now consider a circular ring instead of the block and the fact it will roll down the surface without slipping. What will be the value of the angle at which the ring will y o the bowl surface?

Explanation / Answer

theta = cos^-1(2/3) = 48.12 degrees

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