A stick with a length of 1m is supported by a knife edge at the 50 cm mark (midd

Question

A stick with a length of 1m is supported by a knife edge at the 50 cm mark (middle). Two masses m1: 0.4 kg and m2: 0.6 kg are hanging.. m1 20 cm from the left end and m2 20 cm from the right end of the stick. Gravity: 10 m/s

Calculate the torque created by m1.

Does this torque rotate the stick clockwise or counterclockwise?

Calculate the torque created by m2.

Clockwise or counterclockwise?

Where should you place a 3rd mass such that the stick is at equilibrium? Closer to m1,m2, or doesn't matter?

Find the distance with respect to the support that the third mass m3: 0.3, should be placed for the stick to be in equilibrium?

Please show all work! Thanks!

Explanation / Answer

1. by m1    = r x mg = 0.30 x 0.4 x 9.81 = 1.1772 or 1.2 N.m

counterclockwise

by m2 = 0.30 x 0.6 x 9.81 = 1.7658 or 1.8    N.m

clockwise

2 .   0.3 x r x 9.81 = 1.7658 - 1.1772

r = 0.2 m  

so 20 cm from support in left side.

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