A piece of gold with a mass of 5.50 kg and density of 19300 kg/m 3 is suspended
ID: 2121839 • Letter: A
Question
A piece of gold with a mass of 5.50 kg and density of 19300 kg/m3 is suspended from a string and then totally immersed in a beaker of water. Using density of water is 1000 kg/m3
a) Determine the volume of the piece of gold.
b) Determine buoyant force on the gold when it is submersed.
A gas is taken through the cycle illustrated here. During one cycle, how much work is done by an engine operating on this cycle?
A piece of gold with a mass of 5.50 kg and density of 19300 kg/m3 is suspended from a string and then totally immersed in a beaker of water. Using density of water is 1000 kg/m3
a) Determine the volume of the piece of gold.
b) Determine buoyant force on the gold when it is submersed.
HTML Editor 2.A gas is taken through the cycle illustrated here. During one cycle, how much work is done by an engine operating on this cycle?
A) 3PVB) 2PV
C) 4PV
D) PV
3. An object has a weight of 400 N when it is dry. When it is completely submerged in water is has a weight of 150 N. What is the density of the material is the density of water is 1000 kg/m3? A) a. 2300 kg/m3
B) c. 1200 kg/m3
C) b. 4500 kg/m3
D) d. 1600 kg/m3
4. 4.50 moles of an ideal gas is at 560K. Is the gas undergoes an adiabatic compression and 3750 J of work is done on the gas, what is the final temperature of the gas? A) c. 2590 K
B) b. 572 K
C) a. 627 K
D) d. 977 K
Explanation / Answer
1)
a)the volume of the gold piece is
V = (m/p)
where m is mass of gold and p is its density
b)the force is
F = p x V x g
where g = 9.8 m/s^2
2)the work done is
W = dP x dV = P x 3V = 3PV
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