When two lenses are used in combination, the first one forms an image that then

Question

When two lenses are used in combination, the first one forms an image that then serves as the object for the second lens. The magnification of the combination is the ratio of the height of the final image to the height of the object. A 1.20cm -tall object is 50.0cm to the left of a lens of focal length of magnitude 40.0cm . A second lens, this one having a focal length of magnitude 60.0cm , is located 300cm to the right of the first lens along the same optic axis.

Explanation / Answer

Part C)

Apply 1/f = 1/p + 1/q

1/-40 = 1/50 + 1/q

q = -22.2 cm --> This is I2

h'/h = -q/p

h'/1.2 = -(-22.2)/50

h' = .533 cm

Part D)

For the second lens

1/60 = 1/322.2 + 1/q

q = 73.7 cm --> Final image location

h'/h = -q/p

h'/.533 = -73.7/322.2

h' = -.122 m (Negative means its inverted - ignore the negative if needed)

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