is directed perpendicularly into the page. An external agent pulls the rod to th
ID: 2122379 • Letter: I
Question
is directed perpendicularly into the page. An external agent pulls the rod to the left with a constant speed of
To answer the questions below you will eventually need to compute the motional EMF in the moving bar.
(b) For as long as the constant 7.50-m/s speed is being maintained, what is the absolute value of the current in each of the two resistors?
in the 2.20-%u03A9 resistor
in the 4.80-%u03A9 resistor
(c) At what rate must the external agent do work in order to maintain the constant 7.50-m/s speed for the sliding rod?
answer in W
(e) What is the magnitude of the force which the external agent must apply to the rod in order to keep it moving at 7.50 m/s?
answer in N
(f) What is the electric field in the moving rod while it is being pulled to the left at 7.50 m/s? (This electric field is actually only in that part of the moving rod which is in between the stationary conducting bars.)
magnitude: answer ( V/m )
Explanation / Answer
emf e=B*l*V= 5.445 V.......
B) R1=2.2 ohms......=i1=V/R1=2.475amps.....
i2=V/R2=1.134 amps.....
C) power=19.65W....
e) Force F=P*V=19.65*7.5=147.39 N...
f) electric field E=V/d=5.445/.33=16.5 V/m
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.