in each case, q-left = -2,-1,0,1,or 2 and q-right=-2,-1,0,1, or 2 Exercise 15.AF
ID: 2122434 • Letter: I
Question
in each case, q-left = -2,-1,0,1,or 2 and q-right=-2,-1,0,1, or 2Exercise 15.AF.16
In each case below, match the electric field on the left with the most appropriate charge distribution on the right.
---Select---q left = +2, q right = +2 q left = -2, q right = +2q left = -2, q right = -2q left = 0, q right = -1 q left = -2, q right = +1q left = 0, q right = 0q left = +2, q right = 0 Electric field lines point radially out from qleft. ---Select---q left = +2, q right = +2 q left = -2, q right = +2q left = -2, q right = -2q left = 0, q right = -1 q left = -2, q right = +1q left = 0, q right = 0q left = +2, q right = 0 ---Select---q left = +2, q right = +2 q left = -2, q right = +2q left = -2, q right = -2q left = 0, q right = -1 q left = -2, q right = +1q left = 0, q right = 0q left = +2, q right = 0 ---Select---q left = +2, q right = +2 q left = -2, q right = +2q left = -2, q right = -2q left = 0, q right = -1 q left = -2, q right = +1q left = 0, q right = 0q left = +2, q right = 0 No field exists. ---Select---q left = +2, q right = +2 q left = -2, q right = +2q left = -2, q right = -2q left = 0, q right = -1 q left = -2, q right = +1q left = 0, q right = 0q left = +2, q right = 0 Electric field lines point radially towards qright. ---Select---q left = +2, q right = +2 q left = -2, q right = +2q left = -2, q right = -2q left = 0, q right = -1 q left = -2, q right = +1q left = 0, q right = 0q left = +2, q right = 0 ---Select---q left = +2, q right = +2 q left = -2, q right = +2q left = -2, q right = -2q left = 0, q right = -1 q left = -2, q right = +1q left = 0, q right = 0q left = +2, q right = 0
Explanation / Answer
1) -2 , -2
2)+2,0
3)-2 , +1
4)+2,+2
5) both 0
6)0,-1
7)-2,+2
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.