then released and oscillates about an equilibrium position. Its motion is descnb

Question

then released and oscillates about an equilibrium position. Its motion is descnbed by: y = (0.40 m) cos [(5.0 rad/s)t] meters. How large is the mass? 0.010 kg 0.20 kg 2.0 kg 5.0 kg 0.50 kg 0.020 kg 8.0 kg 0.32 kg In a laboratory experiment, a uniform bar of mass 4 kg is held in equilibrium by the rope and pulley system shown. The ropes are massless and the pulleys are frictionless. What is the value of the mass M2? The angle theta equals 30 degree . 4 kg 3 kg 3.5 kg 7 kg 5 kg Not close to any of the above. Four masses of 3.0 kg each are arranged in a square on massless rods, as shown. The of the square are 0.50 m long. What is the moment of inertia for rotation about an axis

Explanation / Answer

what about m1 and alpha angle?? i assume m1 = m2 and alpha=theta..

T = mg

on resolving to components, two T sin(thetas) act upward to balance the bar..

for equilibrium, 2 T sin(theta) = 4 x g

i.e 2 x m x g x sin30 = 4 x g

m = 4 kg..

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