explain for full rate Let the gravitational potential energy, U, of an Earth-sat
ID: 2123023 • Letter: E
Question
explain for full rate
Let the gravitational potential energy, U, of an Earth-satellite system be defined as zero for the two bodies. If the satellite is in a noncircular orbit, there may be two points tYe ovb , a and b, sue' Ua = 3Ui>. The kinetic energy of the satellite at point a is: an object of mass 3m, initially at rest, explodes breaking into two fragments of mass M and 2M respect which statement concerning the fragments after the explosion is true? They may fly off at right angles. They may fly off in the same direction. The larger fragment will have twice the speed of the smaller fragment. The smaller fragment will have twice the speed of the larger fragment. The smaller fragment will have four times the speed of the larger fragment. The figure shows a typical data pattern obtained in the lab experiment for Unit 3 for the case in which the target and projectile bells have unequal mass. The collision between the two balls occurs on an elevated track and the balls the fall onto a record sheet below. No vertical velocities are imparted during the collision. The zero point is directly below the initial position of the target ball. The point labeled no-collision is where the projectile ball lands when there is no collision. The numbered points represent the landing spots of the projectile and/or target balls after several different collisions with different angles of impact. Based on the figure, what is the approximate ratio of the mass of the target ball to the mass of the projectile ball?Explanation / Answer
the cart is moving with velocity of 20 m/s so KE posssesed by cart=0.5*m*v^2
the maximum height it can reach is when its all KE is converted into gravitational PE
so mgh= 0.5*m*v^2
so
9.8*h=0.5*400
so h=20.4m
so it cannot go beyond 20.4 m
so the correct answer is D
as after that its PE will start converting into KE
answer id
D
2).since PE is inversly propotinal to distance between them so Ra< Rb
and since TE is constant so
answer is B
1). their linear momentum will be constant and also zero as initialy it was zero so
they must fly in opposite direction
also
m1v1=2mv2
so v1=2v2
so the answer is D
2).A
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