suppose that the rate at which you work on a hot day is inversely proportional t

Question

suppose that the rate at which you work on a hot day is inversely proportional to the excess temperature above 75 degree celcius. one day the temperature is rising steadily, and you start studying at 2 p.m. you cover 20 pages the first hour and 10 pages the second hour. at what time was the temperature 75 degree Celcius.

So I figure this one needs to be an equation of dr/dt that can be solved with r and r two=10 but I can't seem to figure out the enitial equation to solve for the spacific solution.

Explanation / Answer

dr/dt=k*(T-75)

.

==> now Temperature rises steadily

==> T=c*t

==> dr/dt=K*(ct-75)

==> dr=K*(ct-75)*dt

now r1=20 at t=0

and r2=10 at t=1 Hr

this is the equation i figured

we need to calculate "c" but i am falling short of equation

there are two variables namely K and C

but we have only one equation

so my guess is some data is missing in the question

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