alulate the net vield of ATP in liver cels from the complete conversion of 1 mol

Question

alulate the net vield of ATP in liver cels from the complete conversion of 1 mol of glutamate and 1 mol a ame must enter the citric acid cycle as true substrates in order to be completely oxidized to CO.). Assume that all 10 (0 ond to I mol of urea (via de-amination and the urea cycle) and 8 mol CO, (note the carbon skeletons of glutamate and alanine NADH and FADH2 produced will enter the ETC and that 1 NADH-2.5 ATP and I FADH. 1.5 ATP. Assume that all tne glutamate is deaminated by glutamate dehydrogenase and that the enzyme uses only NAD (rather than NADP"). Assume all the alanine combines with 1 mol of OAA to produce 1 mol of pyruvate and 1 mol of aspartate via transamination. In other words, assume the -NH2 group in the carbamoyl phosphate comes solely from the glutamatic acid, and that the second-NH2 group in urea comes solely from aspartic acid that is produced from alanine. You musit show your reasoning to get full credit for this problem Glutamate +alanine +HCOsurea +8 CO

Explanation / Answer

The given cycle is interlinked to Kreb's and urea cycle. So, from the given information the cycle involves 4 Kreb's cycles and 1 urea cycle.

4 Kreb's cycle energetics = 4*13 ATP's accoridng to the given NADH2 and FADH values i.e., 2.5 and 1.5.

4*13= 52 ATP's in urea cycle we are getting 2 more ATP's total net ATP's are 54 ATP's

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