Academic Integrity: tutoring, explanations, and feedback — we don’t complete graded work or submit on a student’s behalf.

Question 6 A traffic light of weight 100 N is supported by two ropes as shown. W

ID: 2123571 • Letter: Q

Question

Question 6

A traffic light of weight 100 N is supported by two ropes as

shown. What are the tensions in the ropes?

1. 50 N

2. 63 N

3. 66 N

4. 83 N



Question 8

Simple pendulum A swings back and forth at twice the frequency of simple pendulum B.

Which statement is correct?

1. Pendulum B is twice as long as A.

2. Pendulum B is twice as massive as A.

3. The mass of B is four times the mass of A.

4. The length of B is four times the length of A.




Question 9

A mass of 200g hung is from an ideal spring causes it to stretch by 8.4 cm.

What is the period of oscillation for this spring/mass system?

1. 0.093 s

2. 0.58 s

3. 10.8 s

4. 23.3 s





Question 10

In a hydraulic garage lift, the small piston has a radius of 5.0 cm and the large piston has

a radius of 15 cm.

What force must be applied on the small piston in order to lift a car weighing 20,000 N

on the large piston?

1. 6.7 x 103 N

2. 5.0 x 103 N

3. 2.9 x 103 N

4. 2.2 x 103 N

Explanation / Answer

Question 6
2*T*sin 37 = 100
so Tension T = 83.082 ... option 4


Question 7
option 3 is correct

Question 8
frequency is inversely proportional to sqare root of lenght ...

as freq_A = 2 * freq_B

so... lenght_B = 4 times lineght_ A

option 4 is correct


Question 9

for equillibrium ... m*g = k*x
so.. 0.2 * 9.8 = k * 0.084
so spring const.. k = 23.33 N/m
mass = 200g = 0.2 kg..

preriod = 2*pi * sqrt ( m / k ) = 2*pi*sqrt ( 0.2 / 23.33) = 0.58175 secs.... option 2


Questin 10

pressure required = weight of car / area of piston = 20000 / (pi * 0.15^2)

so pressure at small piston = 20000 / (pi * 0.15^2)
so force required = pressure * area = (20000 / (pi * 0.15^2) ) * pi * 0.05^2   = 2222.22 N
option 4 is correct

Hire Me For All Your Tutoring Needs
Integrity-first tutoring: clear explanations, guidance, and feedback.
Drop an Email at
drjack9650@gmail.com
Chat Now And Get Quote