Q1. A proton is accelerated from rest to 0.75c. style=\"font-size: 12.000000pt;
ID: 2123764 • Letter: Q
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Q1. A proton is accelerated from rest to 0.75c. data-mce-style="font-size: 12.000000pt; font-family: 'times new roman';">
a. Find the rest energy (in Joules) contained in a single proton. (mass=1.67 x10-27 kg).style="font-size: 12.000000pt; font-family: 'times new roman';" data-mce-style="font-size: 12.000000pt; font-family: 'times new roman';">
b. Find the relativistic kinetic energy of the proton moving at 0.75c.style="font-family: 'times new roman'; font-size: 12pt;" data-mce-style="font-family: 'times new roman'; font-size: 12pt;">
c. Find the relativistic momentum of the proton moving at 0.75c.
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Q2. A light beam is traveling in glass (n=1.56) when it hits an air interface with an angle data-mce-style="font-family: 'times new roman'; font-size: 12pt;">style="font-size: 12.000000pt; font-family: 'times new roman';" data-mce-style="font-size: 12.000000pt; font-family: 'times new roman';">
of incidence of 22 degrees. (image link: http://postimg.org/image/wr21lw425 )style="font-family: 'times new roman'; font-size: 12pt;" data-mce-style="font-family: 'times new roman'; font-size: 12pt;">style="font-size: 12.000000pt; font-family: 'times new roman';" data-mce-style="font-size: 12.000000pt; font-family: 'times new roman';">
a. What is the expected angle of refraction?style="font-family: 'times new roman'; font-size: 12pt;">
b. If you increased the angle of incidence, at what angle would you see total internal reflection?style="font-family: 'times new roman'; font-size: 12pt;">style="font-size: 12.000000pt; font-family: 'times new roman'">
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Q3. A light beam reflects off of a plane mirror as shown at right. If the angle of incidence is cut in half compared to what's shown here, what is the new angle of reflection? diagram: http://postimg.org/image/6u5waa84b/style="font-family: 'times new roman'; font-size: medium;">style="font-size: 12pt; font-family: 'times new roman,italic';">style="font-size: 12pt; font-family: 'times new roman';">style="font-size: 12pt; font-family: 'times new roman';">style="font-size: 12pt; font-family: 'times new roman,italic';">style="font-size: 12pt; font-family: 'times new roman';">face="times new roman" size="3">
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55 degreesstyle="font-size: 12pt;">
A proton is accelerated from rest to 0.75c. Find the rest energy (in Joules) contained in a single proton. (mass=1.67 x10-27 kg). Find the relativistic kinetic energy of the proton moving at 0.75c. Find the relativistic momentum of the proton moving at 0.75c. A light beam is traveling in glass (n=1.56) when it hits an air interface with an angle of incidence of 22 degrees. (image link: http://postimg.org/image/wr21lw425 ) What is the expected angle of refraction? If you increased the angle of incidence, at what angle would you see total internal reflection? A light beam reflects off of a plane mirror as shown at right. If the angle of incidence is cut in half compared to what's shown here, what is the new angle of reflection? diagram: http://postimg.org/image/6u5waa84b/Explanation / Answer
according to snells law
n1 sin theta1 = n2 sin theta2
n1 for glass = 1.56
n2 for air = 1
theta1 = 22
theta2 = ?
1.56 sin 22 = 1 x sin theta2
theta2 = 35.76 degrees
as the ray moves from denser to rayere medium then it moves away from normal
in case of total internal reflection the theta 2 will be 90 degrees
1.56 sin theta1 = 1 x sin90
theta1 = 39.87 degrees
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for a plane mirror
the angle of reflection = angle of incidence
so if the incidence angle is cut into half then angle = 55/2 = 27.5 degrees
thus angle of reflection = angle of incidence = 27.5 degrees
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