The Tevatron at the Fermi National Laboratory can accelerate protons to a kineti

Question

The Tevatron at the Fermi National Laboratory can accelerate protons to a kinetic energy of 1 TeV. In one particular experiment the kinetic energy of the protons is 650 GeV. What is the de Broglie wavelength of these protons?

These protons then collide with antiprotons of the same energy moving in the opposite direction. From the results of these collisions we try to understand the inner structure of protons. If the radius of the proton (and the antiproton) is 0.94 fm, then what fraction of this distance can we probe using the Tevatron accelerator?

Explanation / Answer

Ah, j/k, figured it out. Its the ratio the de Broglie wavelength and it's radius (0.94fm in this case).

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