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ID: 2124048 • Letter: F

Question

For full points I would like to see the work and a correct answer.


Thank you.


A body oscillates with simple harmonic motion along the x-axis.  Its displacement varies with time according to the equation

x=5sin(piT + pi/3).  Find the magnitude of the acceleration in m/s^2 of the body at at=1 second.  


A body oscillates with simple harmonic motion along the .v-axis. Its displacement varies with time according to the equation x = 5 sin (pit + PI/3). Find the magnitude of the acceleration in m/s2 of the body at t = 1 second.

Explanation / Answer

To get velocity you need the first derivative
= -5.0 p sin ( pt)

And for acceleration take the derivative of this
= -5.0 p^2 cos ( p t)

Hence at the time of 1 sec the acceleration is
- 5.0 p^2 cos ( p)

Note that the direction is the exact opposite to the direction of the displacement.