First, we start with some background information. The length of this carbon chai

Question

First, we start with some background information. The length of this carbon chain is about L=18.5e-10m, and there are 22 electrons. Due to the exclusion principle, only one electron can be in each state. However, because of electron spin, which has two states, each standing wave can accommodate 2 electrons. Therefore, we need 22/2 = 11 standing wave states to accommodate all these electrons. Energy can be absorbed when an electron jumps into the next highest (i.e. the 12th) state.

Thus, we want to figure out the energies corresponding to the 11th and 12th standing wave states, and set that equal to the absorbed photon energy.

Question:

1. Determine the wavelengths of standing waves on the molecule or %u2018string%u2019. The only rule is that the wave amplitude must be zero at either end. This is exactly the same as for an actual string.

Please help me! Working out please.

First, we start with some background information. The length of this carbon chain is about L=18.5e-10m, and there are 22 electrons. Due to the exclusion principle, only one electron can be in each state. However, because of electron spin, which has two states, each standing wave can accommodate 2 electrons. Therefore, we need 22/2 = 11 standing wave states to accommodate all these electrons. Energy can be absorbed when an electron jumps into the next highest (i.e. the 12th) state. First, we start with some background information. The length of this carbon chain is about L=18.5e-10m, and there are 22 electrons. Due to the exclusion principle, only one electron can be in each state. However, because of electron spin, which has two states, each standing wave can accommodate 2 electrons. Therefore, we need 22/2 = 11 standing wave states to accommodate all these electrons. Energy can be absorbed when an electron jumps into the next highest (i.e. the 12th) state. Determine the wavelengths of standing waves on the molecule or %u2018string%u2019. The only rule is that the wave amplitude must be zero at either end. This is exactly the same as for an actual string.

Explanation / Answer

http://hyperphysics.phy-astr.gsu.edu/hbase/ewav.html

The first table on the site shows the first 3 of 11 states (again, each with two electrons).

The wavelength of the nth state would be:

18.5E-10 or 37E-10

(n/2) n

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