In the figure below, a metal rod is forced to move with constant velocity vvec a

Question

In the figure below, a metal rod is forced to move with constant velocity vvec along two parallel metal rails, connected with a strip of metal at one end. A magnetic field Bvec = 0.310 T points out of the page. If the rails are separated by 25.0 cm and the speed of the rod is 52.0 cm/s, what emf is generated? If the rod has a resistance of 21.0 and the rails and connector have negligible resistance, what is the current in the rod? (Include the sign, taking counterclockwise to be positive.) At what rate is energy being transferred to thermal energy?

Explanation / Answer

emf = BLv

=0.310*(.25)(.52)= 0.0403V

(b)i=emf/R

=(0.0403)/21 =1.919mA

(c)rate is Power P= (i^2)R

=0.77*(10^-6)W

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