Water flows steadily from an open tank. The elevation of point 1 is 10.0 m, and

Question

Water flows steadily from an open tank. The elevation of point 1 is 10.0 m, and the elevation of points 2 and 3 is 2.00 m. The cross sectional area at point 2 is 4.80*10^-2 m^2; at point 3 where the water is discharged, it is 1.6*10^-2 m^2. The cross sectional area of the tank is very large compared to the cross sectional area of the pipe.

a) Calculate the volume of water that flows accross the exit of the pipe in 1.00 seconds.

b) What is the speed of the water at point 2?

In the circuit below, determine the power (absorbed or generated) by the voltage source V5 For the circuit shown, find: For the circuit below, determine the voltage vx the voltage vab, and the power (generated or absorbed) by the 3A source.

Explanation / Answer

A)

use bernoulli's equation for 1 to 3, take v1 to equal zero and P3 = P1

P1/pg + z1 = P3/pg + v3^2/2g + z3

v3 = sqrt(2g(z1 - z3)) = sqrt(2*9.81(10 - 2)) = 12.53 m/s

Q = A3*v3 = .2005 m^3/s

B) at point 2 and 3 (both are at same height so)

A2V2 = A3V3

so V2 = A3V3/A2 = 4.1 m/s

Related Questions

Navigate

• Browse (All)
• Browse W
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.