A copper bowl of mass m 1 contains a mass m 2 of water, both at temperature T (w

Question

A copper bowl of mass m1 contains a mass m2 of water, both at temperature T (which is below the boiling point of water). A very hot copper cylinder with mass m3 is dropped into the water, causing the water to boil, with a mass m4 being converted to steam. The final temperature of the system is 100?C. Neglect energy transfers with the environment. (a) How much energy is transferred to the water as heat? (b) How much to the bowl?(c) What is the original temperature of the cylinder? The specific heat of water is cw, and of copper is cc. The latent heat of vaporization of water is Lv. State your answers in terms of the given variables, assuming we are working with Celsius as our temperature scale throughout.

Explanation / Answer

(a) Heat transferred to water = m2*cw*(100-T) + m4*Lv cal

(b) Heat transferred to the bowl = m1*cc*(100-T) cal

(c) Heat lost by cylinder = heat gained by bowl + heat gained by water
m3*cc*(Ti-100) = m2*cw*(100-T) + m4*Lv + m1*cc*(100-T)

Ti = 100 + (m2*cw*(100-T) + m4*Lv + m1*cc*(100-T))/m3*cc

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.