help me with from part p-s help me with from part p-s help me with from part p-s

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help me with from part p-s

help me with from part p-s

help me with from part p-s

help me with from part p-s

help me with from part p-s

help me with from part p-s

In a classroom demonstration, an instructor tosses her keys Westward and slightly Upward. A set of motion sensors, attached to a computer, is used to record the position of the keys with respect to a mark on the floor at the instructor's feet. Six positions are recorded, in meters; there are 0.2 of a second between each data point. You are given the computer output in the table below; the direction of each horizontal position is West, and the direction of each vertical position is Up (i.e. above the floor).

Key Toss Tracking   Time     Horizontal Position   Vertical Position (s) (m) (m) 0.0 0.6 2.2 0.2 1.5 2.744 0.4 2.4 2.896 0.6 3.3 2.656 0.8 4.2 2.024 1.0 5.1 1

Explanation / Answer

p) at t = 0.1s, v1 = sqrt(Vx^2 + vY^2) = 5.258 m/s

   at t = 0.3s, v2 = sqrt(Vx^2 + vY^2) = 4.657 m/s
  
   v2-v1 = -0.601 m/s

   theta = tan^-1( V2y-v1y / v2x - v1x) = -90 degrees


q) at t = 0.3s, v1 = sqrt(Vx^2 + vY^2) = 4.56 m/s

   at t = 0.5s, v2 = sqrt(Vx^2 + vY^2) = 4.658 m/s
  
   v2-v1 = -0.094 m/s

   theta = tan^-1( V2y-v1y / v2x - v1x) = -21.6 degrees


r) at t = 0.5s, v1 = sqrt(Vx^2 + vY^2) = 4.567 m/s

   at t = 0.7s, v2 = sqrt(Vx^2 + vY^2) = 5.036 m/s
  
   v2-v1 = 0.379 m/s

   theta = tan^-1( V2y-v1y / v2x - v1x) = -90 degrees

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