Point P1 is on the perpendicular bisector of the dipole and P2 is along the axis

Question

Point P1 is on the perpendicular bisector of the dipole and P2 is along the axis of the dipole in the direction of the sipole moment vector P. P1 and P2 are both a distance of 100 m from the center of the dipole.  The magnitude of each of the charges is 4.7

Point P1 is on the perpendicular bisector of the dipole and P2 is along the axis of the dipole in the direction of the sipole moment vector P. P1 and P2 are both a distance of 100 m from the center of the dipole. The magnitude of each of the charges is 4.7 mu C with the direction of the dipole vector P from the negative charge to the positive charge. What is the magnitude of the electric field at P1 answer in units of N/C. What is the magnitude of the electric field at P2 answer in units of N/C.

Explanation / Answer

p = q*2a = 4.7 * 10^(-6) *1.4 = 6.58*10^(-6)

E(P1) = kp/d^3 = 9*10^9*6.58*10^(-6) / 100^3 = - 0.059 N/C

E(P2) = 2*0.059 = 0.118 N/C

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