Engineering Electromagnetics with CD 7TH Edition Chapter 9 Problem 8 Textbook So

Question

Engineering Electromagnetics with CD 7TH Edition Chapter 9 Problem 8 Textbook Solution

A perfectly conducting filament is formed into a circular ring of radius a. At one point, a resistance R is inserted into the circuit, and at another a battery of

voltage Vo is inserted. Assume that the loop current itself produces negligible magnetic field.

Eq (4):  emf = closed curve integral E dot dL = (- d/dt) * surface integral B dot dS

(a) Apply Faraday's law, Eq (4), evaluting each side of the equation carefully and independently to show the equality;

(b) repeat (a), assuming the battery is removed, the ring is closed again, and a linearly increasing B field is applied in a direction normal to the loop surface.

Please show the derivation

Explanation / Answer

please post the figure

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