hello everyone, i have some quistions i would like you guys answer then please A
ID: 2126240 • Letter: H
Question
hello everyone,
i have some quistions i would like you guys answer then please ASAP
thanks
1) A particle of charge +2.56 x 10-6 C is 12.4 cm distant from a second particle of charge -1.55 x 10-6 C. Calculate the magnitude of the electrostatic force between the particles.
2)Two equally charged particles, held 4.1 x 10-3 m apart, are released from rest. The initial acceleration of the first particle is observed to be 6.7 m/s2 and that of the second to be 13 m/s2. If the mass of the first particle is 6.7 x 10-7 kg, what are (a) the mass of the second particle and (b) the magnitude of the charge (in C) of each particle?
3) Three particles are fixed on an x axis. Particle 1 of charge q1 is at x = -a and particle 2 of charge q2 is at x = +a. If their net electrostatic force on particle 3 of charge Q is to be zero, what must be the ratio q1/q2 when particle 3 is at (a) x = +0.722a and (b) x = +1.87a?
4) Earth's atmosphere is constantly bombarded by cosmic ray protons that originate somewhere in space. If the protons all passed through the atmosphere, each square meter of Earth's surface would intercept protons at the average rate of 1200 protons per second. What would be the electric current in amperes intercepted by a 49 x 107 km2 area on the planet?
5)A charged nonconducting rod, with a length of 2.13 m and a cross-sectional area of 3.20 cm2, lies along the positive side of an x axis with one end at the origin. The volume charge density ? is charge per unit volume in coulombs per cubic meter. How many excess electrons are on the rod if ? is (a) uniform, with a value of -2.67
Explanation / Answer
1. F = kq1q2/r^2 = 9*10^9 * 2.56*1.55*10^-12/0.124^2 =2.322 N
4.current = q/t = 1200*1.6*10^-19*49*10^7*10^6 = 0.9408 A
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