It is 2014 and space cadets are training at the World Ceres, where gravity is ne
ID: 2126490 • Letter: I
Question
It is 2014 and space cadets are training at the World Ceres, where gravity is negligable. They use a coordinate system with orgin at Ceres surface, y axis up. Today, Carmen is correctly is executing a series of maneuvers. At t=0, 3 minutes after maneuver 5 ends, she is crossing the y axis, 20km up from the surface, moving with vz-400m/s, and she begins the 6th manuever, which consists of 40s of constant accelertation, to be followed (after 90s of no acceleration) by manuever 7. At t=30s her velocity is 500m/s in a direction of 36.9 angle from negative z toward positive y.
1. Find her veolcity at t= 2 minutes
2. Find her position component at t=20s
3. Find her position at t= 2minutes
Explanation / Answer
Her inital velocity is (0,0,-400) m/s (now to be noted v(0))
Her initial position is (0,20000,0) m (now to be noted x(0))
At t=30s, her velocity is (0, (500sin(36.9)), -(500cos(36.9)) m/s
which is (0,300,-400) m/s
Change in velocity in 30s is (0,300,0) m/s
Dividing this by change in time of 30s,
acceleration over this time is (0,10,0) m/s^2
This acceleration continued for 10 more seconds.
Then final velocity at t=30s would be (0,400,-400)
Since her velocity does not change afterward as acceleration becomes 0,
answer to part a is (0,400,-400)
b.
Use the formula
x = x(o) + v(o)t + (1/2)at^2
= (0,20000,0) + (0,0,-400)(20) + (1/2)(0,10,0)(20^2)
= (0,22000,-8000) m
c.
Calculate it as two segments
Change in position during first 40s.
dx1 = v(0)t + (1/2)at^2
= (0,0,-400)(40) + (1/2)(0,10,0)(40^2)
= (0,8000,-16000) m
Change in position during next 80 seconds
dx2 = v(0)t + (1/2)at^2
= (0,400,-400)(80) + (1/2)(0)(80^2)
= (0,12000,-32000) m
Final position
= x(0) + dx1 + dx2
= (0,20000,0) + (0,8000,-16000) + (0,12000,-32000)
= (0,40000,-48000) m
Summary
1. (0,400,-400) m/s
2. (0,22000,-8000) m
3. (0,40000,-48000) m
In case you are not familiar with this way of denoting position, veloicty, and acceleration,
First, second, and third values indicate x, y, and z values respectively.
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