Near the end of a marathon race, the first two runners are separated by a distan

Question

Near the end of a marathon race, the first two runners are separated by a distance of 45.0 m. The front runner has a velocity of 3.45 m/s, and the second a velocity of 4.25 m/s.style="font-family: verdana, helvetica, sans-serif; font-size: 13px; line-height: 20px;">color="red">style="font-family: verdana, helvetica, sans-serif; font-size: 13px; line-height: 20px;">color="red">style="font-family: verdana, helvetica, sans-serif; font-size: 13px; line-height: 20px;">color="red">style="font-family: verdana, helvetica, sans-serif; font-size: 13px; line-height: 20px;">

style="font-family: verdana, helvetica, sans-serif; font-size: 13px; line-height: 20px;">color="red">style="font-family: verdana, helvetica, sans-serif; font-size: 13px; line-height: 20px;">color="red">style="font-family: verdana, helvetica, sans-serif; font-size: 13px; line-height: 20px;">color="red">style="font-family: verdana, helvetica, sans-serif; font-size: 13px; line-height: 20px;">

0.8 m/s faster than the front runner.

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____ mstyle="font-size: 12px;">

Explanation / Answer

t1= 250/3.45= 72.46 s

t2 = (250+45)/4.25 = 69.41 s

t2< t1 so second runner will win

c) S1 = 3.45*t2= 239.4645m

distand=ce = 250-239.4645=10.56m

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