As shown in the figure, a square has sides of d = 7.0 cm with a charge of Q = -

Question

As shown in the figure, a square has sides of d = 7.0 cm with a charge of Q = -15.0 µC at one corner (a) and with charges of q = +5.0 µC at the remaining three corners (b, c, and d).style="color: #dd0000;" color="#dd0000" data-mce-style="color: #dd0000;">style="color: #dd0000;" color="#dd0000" data-mce-style="color: #dd0000;">style="color: #dd0000;" color="#dd0000" data-mce-style="color: #dd0000;">style="color: #dd0000;" color="#dd0000" data-mce-style="color: #dd0000;">style="color: #dd0000;" color="#dd0000" data-mce-style="color: #dd0000;">

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As shown in the figure, a square has sides of d = 7.0 cm with a charge of Q = -15.0 A mu C at one corner (a) and with charges of q = +5.0 A mu C at the remaining three corners (b, c, and d).

Explanation / Answer

assddfield at the center due to the lower left charge 1 and upper right charge q will cancel each other.

so field due to Q is towards Q along the line joining Q and q and similarly,field due to q is away from q along the line joining Q and q.

so net electric field will add up as they are in the same direction.

so field=9*10^9*Q/(sqrt(2)*d/2)^2 +9*10^9*q/(sqrt(2)*d/2)^2

=9*10^9*(20*10^(-6))/(2.45*10^(-3))

=7.34*10^7 N/C

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