A positive charge ( q = +6.0 C) starts from point A in a constant electric field

Question

A positive charge (q = +6.0 C) starts from point A in a constant electric field and accelerates to point B. The work done by the electric force is WAB = +3.4 10-3 J. Determine the potential difference VB - VA between the two points. Be sure to include the proper algebraic sign.

A positive charge (q = +6.0 mu C) starts from point A in a constant electric field and accelerates to point B. The work done by the electric force is WAB = +3.4 times 10-3 J. Determine the potential difference VB - VA between the two points. Be sure to include the proper algebraic sign.

Explanation / Answer

the potential difference between the points q(VA-VB)=work done by the electric field

+6.0

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